(2x+9)^2+(3x+1)=180

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Solution for (2x+9)^2+(3x+1)=180 equation: 



(2x+9)^2+(3x+1)=180

We move all terms to the left:

(2x+9)^2+(3x+1)-(180)=0

We get rid of parentheses

(2x+9)^2+3x+1-180=0

We add all the numbers together, and all the variables

3x+(2x+9)^2-179=0

We move all terms containing x to the left, all other terms to the right

3x+(2x+9)^2=179

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